First select Bob (since he MUST be part of the 3-person selection).sud21 wrote:If three people are to be selected from eight people, who include Bob and Nancy, how many ways are possible that Bob, not Nancy is selected?
This leaves 7 people, and Nancy is one of them.
We need to choose 2 more people from the remaining 7 people such that Nancy is not one of them.
So . . . ask Nancy to leave the room (this guarantees that she is not selected)
In how many ways can we select 2 people from 6 people (none of whom is Nancy)?
We can accomplish this in 6C2 (15) ways.
The answer is 15
Cheers,
Brent
