2^(x-2) is a common factor for 2^x and 2^(x-2), so you get:
2^x - 2^(x-2) = 2^(x-2) * [2^2 - 1] = 2^(x - 2) * (4 - 1) = 2^(x - 2) * 3 = 3 * 2^13
This means that x - 2 = 13, so x = 15.
And yes, I do believe this question has been answered before...
what is x
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Deepoe,deepoe wrote:2^x – 2^x-2 = 3(2^13), what is x?
a. 9
b. 11
c. 13
d. 15
e. 17
Don't know if this question already have been asked, if so I'M SORRY
Please type your questions clearly!!!
A better way to write this out would be:
Notice the highlighted part!!!!
2^x - 2^(x-2) = 3 (2^13)
2^x * (1- (1/2^2) ) = 3 * (2^13)
2^x * (3/4) = 3 * (2^13)
2^x = (2^2) * (2^13)
2^x = 2^15
x = 15
[D]
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Sorrykanha81 wrote:Deepoe,deepoe wrote:2^x – 2^x-2 = 3(2^13), what is x?
a. 9
b. 11
c. 13
d. 15
e. 17
Don't know if this question already have been asked, if so I'M SORRY
Please type your questions clearly!!!
A better way to write this out would be:
Notice the highlighted part!!!!
2^x - 2^(x-2) = 3 (2^13)
2^x * (1- (1/2^2) ) = 3 * (2^13)
2^x * (3/4) = 3 * (2^13)
2^x = (2^2) * (2^13)
2^x = 2^15
x = 15
[D]
Could you explain these steps:
2^x * (1- (1/2^2) ) = 3 * (2^13)
2^x * (3/4) = 3 * (2^13)
Thanks!













