fourteenstix wrote:
Plug in a value for x and solve for y.
Let x=3, so that 5^(x-3) = 5� =1.
Plugging x=3 into the equation, we get:
5³ - 5� = 124 * 5^y
124 = 124 * 5^y
1 = 5^y
y=0.
Since the question stem asks for the value of y, our target is y=0.
Now plug x=3 into the answers to see which yields our target of 0.
A quick scan of the answer choices shows that only
C works:
x-3 = 3-3 = 0.
The correct answer is
C.
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