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akshatgupta87
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akshatgupta87 wrote:Q.) Is x > 10^10 ?
(1) x > 2^34
(2) x = 2^35
Someone explain.
Statement 1: x > 2^34.
We need to compare 2^34 to 10^10.
To make the comparison easier, take the square root of each value.
√(2^34) = 2^17.
√(10^10) = 10^5.
Now compare:
2^17 > 10^5
2^17 > (2^5)*(5^5)
2^12 > 5^5
4^6 > 5^5.
4^6 = (4^3)*(4^3) = 64*64 ≈ 4000.
5^5 = 5*(5^4) = 5*625 ≈ 3000.
Thus, 4^6 > 5^5.
Sufficient.
Statement 2: x = 2^35.
Gives us the exact value of x.
Thus, we can determine whether x > 10^10.
Sufficient.
The correct answer is D.












