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Working at their individual rates, Marcus and Latrell can build a certain brick house in 7.5 and 5 hours, respectively.

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Working at their individual rates, Marcus and Latrell can build a certain brick house in 7.5 and 5 hours, respectively.

by BTGmoderatorDC » Wed Sep 29, 2021 6:38 pm

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Working at their individual rates, Marcus and Latrell can build a certain brick house in 7.5 and 5 hours, respectively. When they work together,they are paid $35 per hour. If they share their pay in proportion to the amount of work each does,then what is Marcus’ hourly pay for building the house?

A. $3
B. $6
C. $7
D. $14
E. $21


OA D

Source: Princeton Review
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Re: Working at their individual rates, Marcus and Latrell can build a certain brick house in 7.5 and 5 hours, respective

by swerve » Thu Sep 30, 2021 7:48 am
BTGmoderatorDC wrote: ↑
Wed Sep 29, 2021 6:38 pm
 Working at their individual rates, Marcus and Latrell can build a certain brick house in 7.5 and 5 hours, respectively. When they work together,they are paid $35 per hour. If they share their pay in proportion to the amount of work each does,then what is Marcus’ hourly pay for building the house?

A. $3
B. $6
C. $7
D. $14
E. $21


OA D

Source: Princeton Review
Marcus rate; \(1/7.5\)
Lateral rate; \(1/5\) hrs
Together; \(1/7.5+ 1/5 = 3\) or say \(1/3\)

So, Marcus can make; \(7.5/3\) houses per hour so for \(35\$\) per hour hourly rate
\(35*3/7.5;\) \(14\$\)


Therefore, D
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Re: Working at their individual rates, Marcus and Latrell can build a certain brick house in 7.5 and 5 hours, respective

by rk_gmat » Thu Sep 30, 2021 11:42 am
The ratio of work done by each
Markus : Latrell
= \(\frac{1}{7.5}\) : \(\frac{1}{5}\)
= 2:3 {Multiply both by 15}

Pay is directly proportional to this ratio so they're paid
2x : 3x
Total = 5x = $35 => x =7
Hence, Markus's Pay = 2x = $14

D
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