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Is integer N even?

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Source: — Data Sufficiency |
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by kmittal82 » Wed Aug 10, 2011 4:46 am
(1)
nxn = n
n(n - 1 ) = 0

This means either n=0, or n = 1. Not sufficient

(2)
n - (n^3) = 0
n(1 - n^2) = 0
n(1-n)(1+n)=0

This means n=0, or n=1 or n = -1. Not sufficient

Combining (1) and (2), we get either n=0 or n=1, again, not sufficient

So (E)

Note: I'm considering 0 to be an even number here, i.e. 0 divided by 2 leaves a remainder of 0
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by Spartacus2000 » Wed Aug 10, 2011 7:18 am
Should zero always be considered an even no.?

Does that apply for all questions eg: Set X contains even nos. < 10, in that case can zero be considered a part of this set?
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by Frankenstein » Wed Aug 10, 2011 7:21 am
Spartacus2000 wrote:Should zero always be considered an even no.?

Does that apply for all questions eg: Set X contains even nos. < 10, in that case can zero be considered a part of this set?
Hi,
Yes...Zero is always even.
If set X contains even numbers less than 10, you should consider zero as well. But, if set X contains positive even numbers less than 10, then you shouldn't consider zero because zero is neither positive nor negative.
Cheers!

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by kmittal82 » Wed Aug 10, 2011 7:24 am
Spartacus2000 wrote:Should zero always be considered an even no.?

Does that apply for all questions eg: Set X contains even nos. < 10, in that case can zero be considered a part of this set?
I believe so. No matter what the test, it shouldn't change the fundamental definition of what is an even number, i.e. a number when divided by 2 leaving no remainder. 0 certainly fits this.
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