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by sanju09 » Tue Mar 09, 2010 2:25 am
AB is the chord of a circle with center O. AB is extended to C such that BC = OB. The straight line CO is produced to meet the circle at D. If ∠ACD = y° and ∠AOD = x° such that x = k y, then what is the value of k?
(A) 1
(B) 1 ¼
(C) 2
(D) 2 ¾
(E) 3
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Source: — Problem Solving |

by kstv » Tue Mar 09, 2010 3:11 am
ACO = BOC=Y°
ABO = BOC+BCO = 2Y°=BAO as AO=BO = radius
AOD = X°= kY = OAB+OCA = 2Y+Y = 3Y
k = 3
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