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Judy is 26 years old and Diane is 5 years old. In how many years will Judy be twice as old as Diane?

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Re: Judy is 26 years old and Diane is 5 years old. In how many years will Judy be twice as old as Diane?

by Brent@GMATPrepNow » Tue Dec 15, 2020 7:13 am
BTGmoderatorDC wrote: ↑
Thu Dec 10, 2020 5:34 pm
 Judy is 26 years old and Diane is 5 years old. In how many years will Judy be twice as old as Diane?

A. 16
B. 19
C. 21
D. 24
E. 26


OA A

Source: Princeton Review
Let x = the number of years until Judy is twice as old as Diane

So, 26 + x = Judy's age in x years
And 5 + x = Diane's age in x years

We get the equation: 26 + x = 2(5 + x)
Expand: 26 + x = 10 + 2x
Subtract x from both sides: 26 = 10 + x
Subtract 10 from both sides: 16 = x

Answer: A
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Re: Judy is 26 years old and Diane is 5 years old. In how many years will Judy be twice as old as Diane?

by Scott@TargetTestPrep » Wed Dec 16, 2020 11:13 am
BTGmoderatorDC wrote: ↑
Thu Dec 10, 2020 5:34 pm
 Judy is 26 years old and Diane is 5 years old. In how many years will Judy be twice as old as Diane?

A. 16
B. 19
C. 21
D. 24
E. 26


OA A

Solution:

Let x = the number of years from now when Judy will be twice as old as Diane. We note that x years from now, Judy will be (26 + x) years old, and Diane will be (5 + x) years old. We can create the equation:

26 + x = 2(5 + x)

26 + x = 10 + 2x

16 = x

Answer: A

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