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Grid system

by Akansha » Sun May 29, 2011 10:27 am
Of 75 houses, 48 have a patio. How many houses have a swimming pool?

a. 38 houses have a patio but no swimming pool
b. Number of houses that have a swimming patio and a swimming pool is
equal to the number of houses that have neither pool nor patio


OA is B
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Source: — Data Sufficiency |
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by cans » Sun May 29, 2011 12:53 pm
If P = no. of houses with swimming pool
Q = no. of houses with patio
R = no. of houses with both swimming pool and patio
S = no. of houses with neither pool nor patio
P+Q-R+S = 75 (using venn diagram). We have to find P. Q = 48
P-R+S = 75-48 = 27
A) Q - R = 38 => R = 10.
P-R+S = 27 => P-S=37
One equation, 2 variables. Insufficient.
B) R = s
P-R+S = 27 => P-S+S = 27 => P=27
Hence Sufficient.
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by sivaelectric » Mon May 30, 2011 12:06 am
IMO B
If I am wrong correct me :), If my post helped let me know by clicking the Thanks button ;).

Chitra Sivasankar Arunagiri
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by sivaelectric » Mon May 30, 2011 12:08 am
Just curious, Cans should we go for all that calculation. I think the answer was written on the window. Obvious. :)
If I am wrong correct me :), If my post helped let me know by clicking the Thanks button ;).

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by cans » Mon May 30, 2011 12:17 pm
sivaelectric wrote:Just curious, Cans should we go for all that calculation. I think the answer was written on the window. Obvious. :)
Such calculations are actually not required but i just elaborated so that you won't have any problem in understanding the solution ;)
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by sivaelectric » Mon May 30, 2011 8:38 pm
Thanks Cans ;)
If I am wrong correct me :), If my post helped let me know by clicking the Thanks button ;).

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