Evenly and odd

This topic has expert replies
Senior | Next Rank: 100 Posts
Posts: 66
Joined: Wed Jul 13, 2011 2:27 pm
Followed by:2 members

Evenly and odd

by abhirup1711 » Wed Jun 26, 2013 2:35 am
How many odd integers are greater than integer X and less than the integer y?
1. There are 12 even integers greater than x and less than y
2. there are 24 integers greater than X and less than Y
Source: — Data Sufficiency |

User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pm
Location: New York, NY
Thanked: 13060 times
Followed by:1906 members
GMAT Score:790

by GMATGuruNY » Wed Jun 26, 2013 3:27 am
abhirup1711 wrote:How many odd integers are greater than integer X and less than the integer y?
1. There are 12 even integers greater than x and less than y
2. there are 24 integers greater than X and less than Y
Statement 1: There are 12 even integers greater than x and less than y.
Let the 12 consecutive even integers greater than x and less than y be the following:
0, 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22.
Here, x<0 and y>22.
If x=-1 and y=23, then every odd integer between 1 and 21, inclusive, will be greater than x and less than y, for a total of 11 odd integers.
If x=-1 and y=24, then every odd integer between 1 and 23, inclusive, will be greater than x and less than y, for a total of 12 odd integers.
INSUFFICIENT.

Statement 2: There are 24 integers greater than x and less than y.
EXACTLY HALF of these 24 consecutive integers must be odd.
Thus, the number of odd integers greater than x and less than y = 12.
SUFFICIENT.

The correct answer is B.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3