-
neerajkumar1_1
- Master | Next Rank: 500 Posts
- Posts: 270
- Joined: Wed Apr 07, 2010 9:00 am
- Thanked: 24 times
- Followed by:2 members
(1) If n = 1/2, then 2n is an integer, but n is not an integer in this case.
If n = 2, then 2n = 4, which is an integer, and n is also an integer here.
No unique answer.
(1) is NOT SUFFICIENT.
(2) If n = 1/3, then 3n is an integer, but n is not an integer in this case.
If n = 2, then 3n = 6, which is an integer, and n is also an integer here.
No unique answer.
(2) is NOT SUFFICIENT.
Combining (1) and (2), 2n and 3n are integers.
2n and 3n can be integers if n is a multiple of 6, so n will always be an integer.
The correct answer is [spoiler](C)[/spoiler].
