Integers

This topic has expert replies
Source: — Data Sufficiency |

User avatar
Legendary Member
Posts: 1460
Joined: Tue Dec 29, 2009 1:28 am
Thanked: 135 times
Followed by:7 members

by selango » Tue Oct 12, 2010 11:54 am
n=15*a=3*5*a?

stmt1,

n=20*a=4*5*a

We dont know whether 3 is a factor of n.

Insuff

stmt2,

n+6=3a

n=3a-6=3(a-2)

n=3,6,9..

n is multiple of 3.

We dont know whether 5 is a factor of n.

Insuff

Combining 1 and 2,

3&5 are factors of n.

n is a multiple of 15

Suff

Pick C
--Anand--

User avatar
GMAT Instructor
Posts: 1449
Joined: Sat Oct 09, 2010 2:16 pm
Thanked: 59 times
Followed by:33 members

by fskilnik@GMATH » Tue Oct 12, 2010 11:54 am
Answer: C

(1) BIFURCATES:

> Take n = 0 , then n is both multiple of 20 (as necessary) and of 15 (answering the question in the affirmative)

> Take n = 20, then n is a multiple of 20 (necessary) but 20 is not a multiple of 15 (answering in the negative)


(2) BIFURCATES:

> Take n = -6, then 0 is a multiple of 3 (as necessary), but -6 is not divisible by 15 (answers in the negative)
> Take n = 15, then 21 is a multiple of 3 (necessary) and 15 is divisible by itself (answers in the positive)


(1+2) DECIDES!

Focus in the question stem, we are looking for factors 3 and 5... From statement (1) we know that n has a factor of 5, from statement (2) we know that n has a factor of 3 (more below), therefore n is divisible by 15.

In fact: n+6 multiple of 3 implies n = (n+6) - 6 divisible by 3 (as a subtraction of two multiples of 3)

Therefore (1+2) answers the question asked, that is, DECIDES about the question concerned!!

Regards,
Fábio
[/quote]
Fabio Skilnik :: GMATH method creator ( Math for the GMAT)
English-speakers :: https://www.gmath.net
Portuguese-speakers :: https://www.gmath.com.br