f(x) = x-x^2 = x(1-x)

f(a) = a(1-a)
f(b) = b(1-b)

Q: Is a(1-a) < b(1-b)

Stmt I

a<b

We have no idea how much bigger 1-a and 1-b are going to be


Eg:

a=1 b=2 then f(a) > f(b)

a=.10 b=.11 f(a) < f(b)

ISNUFF

Stmt II

a^2<b^2

|a|<|b|

a=1 b=2 then f(a) > f(b)

a=.10 b=.11 f(a) < f(b)


Together use same examples to save time:

INSUFF

Choose E

Regards,
CR