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If \(ax + ay + az = 15,\) what is \(x + y + z ?\)

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Re: If \(ax + ay + az = 15,\) what is \(x + y + z ?\)

by beatGMAT1221 » Sun Jul 26, 2020 7:47 am
Given, ax + ay + az = 15
=> a (x+y+z) =15

Find, (x+y+z)

We can see that if we know the value of 'a', we can find the value of (x+y+z).

(1) value of x is insufficient.
(2) Yes, value of a is sufficient to find the value of (x+y+z). So, B is the answer.

If you have any doubt, please let me know.
Please give an upvote. Thanks!
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Re: If \(ax + ay + az = 15,\) what is \(x + y + z ?\)

by Jay@ManhattanReview » Sun Jul 26, 2020 11:03 pm
M7MBA wrote: ↑
Sat Jul 25, 2020 2:59 pm
 If \(ax + ay + az = 15,\) what is \(x + y + z ?\)

(1) \(x = 2\)

(2) \(a = 5\)

[spoiler]OA=B[/spoiler]

Source: Princeton Review
Let's take each statement one by one.

(1) \(x = 2\)

We don't have value of y and z. Insufficient.

(2) \(a = 5\)

From \(ax + ay + az = 15,\) we have \(a(x + y + z) = 15.\) Thus, \(x + y + z = 15/5 = 3\). Sufficient.

Correct answer: B

Hope this helps!

-Jay
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