aaron1981 wrote:The remainder, when a number n is divided by 6, is p. The remainder, when the same number n is divided by 12, is q. Is p < q?
(1) n is a positive number having 8 as a factor.
(2) n is a positive number having 6 as a factor.
OA C
Pl. help me with algebraic way as well as plug-in value way.
Say n = 6k + p; where k is any integer and p is any value among 1, 2, 3, 4, and 5.
Also, say n = 12m + q; where m is any integer and q is any value among 1, 2, 3, 4, ..., and 11.
We have to deduce whether p < q.
Statement 1: n is a positive number having 8 as a factor.
Since n is a positive number having 8 as a factor, n is one among 8, 18, 24, 32, 40, ...
Case 1: If n = 8, the remainder when n = 8 divided by 6 is p = 2, and the remainder when n = 8 divided by 12 is q = 8.
p = 2 < q = 8. The answer is YES.
Case 2: If n = 24, the remainder when n = 24 divided by 6 is p = 0, and the remainder when n = 24 divided by 12 is q = 0.
p = q = 0. The answer is No. No unique answer.
Statement 2: n is a positive number having 6 as a factor.
Since n is a positive number having 6 as a factor, n is one among 6, 12, 18, 24, ...
Case 1: If n = 6, the remainder when n = 6 divided by 6 is p = 0, and the remainder when n = 6 divided by 12 is q = 6.
p = 0 < q = 6. The answer is YES.
Case 2: If n = 24, the remainder when n = 24 divided by 6 is p = 0, and the remainder when n = 24 divided by 12 is q = 0.
p = q = 0. The answer is No. No unique answer.
Statement 1 & 2: n is a positive number having 6 as well as 8 as a factor.
=> n is a positive number having LCM of 6 and 8 as a factor.
LCM of 6 & 8 = 24.
=> n = 24k; k is any integer
Since 24 is divisible by 6 and 8, the reminders would be 0, thus p = q = 0. The answer is NO. A unique answer.
The correct answer:
C
Hope this helps!
Relevant book:
Manhattan Review GMAT Data Sufficiency Guide
-Jay
_________________
Manhattan Review GMAT Prep
Locations:
New York |
Bangalore |
Guangzhou |
Buenos Aires | and many more...
Schedule your free consultation with an experienced GMAT Prep Advisor!
Click here.