mitzwillrockgmat wrote: 2) given bd = 25 , can i use the pythagorean theorem to determine that bc and cd could be 9 and 16?? although i we wont know which side is 9 and 16.
does this make sense??

sumanr84 wrote:

mitzwillrockgmat wrote: 2) given bd = 25 , can i use the pythagorean theorem to determine that bc and cd could be 9 and 16?? although i we wont know which side is 9 and 16.
does this make sense??

You cannot make this assumption here, although it fits here well,

all you can say is X^2 + Y ^2 = 25 ^2,

AB ^2 + AD ^2 = 25 ^2

mitzwillrockgmat wrote: okie got it! thanks!

mitzwillrockgmat wrote:In the figure shown (attached), what is the area of the circular region with center O and diameter BC?

(1) BC/AB = 3/4
(2) BD = 25

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.



The following is how i solved it. pls confirm i am on the right path!

1) given bc/ab =3/4 we cant conclude anything except bc is 3x and ab 4x. so radius is 1.5x at best according to this stat.

2) given bd = 25 , can i use the pythagorean theorem to determine that bc and cd could be 9 and 16?? although i we wont know which side is 9 and 16.

combined, i know that bc is 3x so it must be the side that is 9.

hence radius is 4.5 and area is (pie)4.5^2

does this make sense??