simba12123 wrote:Seed mixture x is 40 percent ryegrass and 60 percent bluegrass by weight, seed mixture y is 25 percent ryegrass and 75 percent fescue. If a mixture of x and y contains 30 percent ryegrass. WHat percent of the weight of the mixture is x?
a. 10 %
b.33.3%
c.40%
d.50%
e.66.67%
qa is b
although the answer explanation is nice in the back of the og 11 book, I am looking for a faster and less algebraic approach. ANy help?
A less algebraic approach would be to
use the answer choices.
The answers represent the percentage of the mixture that will be X. Let's start with C, which says the mixture will be 40% X, 60% Y.
Let's say we use 40 of X and 60 of Y, so our total mixture is 40 + 60 = 100.
X is 40% ryegrass, giving us .4 * 40 = 16 ryegrass.
Y is 25% ryegrass, giving us .25 * 60 = 15 ryegrass
So we have 16 + 15 = 31 ryegrass in the total mixture.
What percent of the total mixture is ryegrass? 31/100 = 31%
Since we need the mixture to be 30% ryegrass, we need to use just a little less X, which has a higher percentage of ryegrass.
So the correct answer must be
B.
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