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Speed problem - Is this solution correct ?

Expert replies
by pbanavara » Sun Nov 09, 2008 9:31 pm
Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking?

A. 2 hours
B. 4 ½ hours
C. 5 ¾ hours
D. 6 hours
E. 7 ½ hours






OA : B
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Source: — Problem Solving |

by raunekk » Sun Nov 09, 2008 10:20 pm
1st cyclist 2nd cyclist

R 6m/h 10m/h


T t t-3

D d =6t d =10(t-3)


Both distances will be sam when they meet...

thus 6t=10(t-3)

t=7.5

thus time taken by 2nd cyclist will be =t-3 = 7.5 - 3 = 4.5

hence B
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by cramya » Mon Nov 10, 2008 6:04 am
Please see attachment.

Hope this helps. Good luck.
Attachments
cyclist.xls
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by jnellaz » Mon Nov 10, 2008 7:30 am
Gents, Thanks for the solutions.
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