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OG11 DS #142

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by awesomeusername » Sat Apr 25, 2009 12:00 am
In the question, for (2), it states:

x > 0 = b

I am not familiar with this type of inequality. Does this mean that x>0 and b=0, or x=b?

thx
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Source: — Data Sufficiency |
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Re: OG11 DS #142

by Vemuri » Sat Apr 25, 2009 4:22 am
awesomeusername wrote:In the question, for (2), it states:

x > 0 = b

I am not familiar with this type of inequality. Does this mean that x>0 and b=0, or x=b?

thx
Please be kind enough to post the question. Not everyone in this forum has the OG.
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by gpaggie07 » Mon Jul 18, 2011 8:30 pm
Nevermind, found it is a typo here: https://www.beatthegmat.com/exponents-qu ... ent=Boston
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by Anurag@Gurome » Mon Jul 18, 2011 9:35 pm
awesomeusername wrote:In the question, for (2), it states:

x > 0 = b

I am not familiar with this type of inequality. Does this mean that x>0 and b=0, or x=b?

thx
The exact question is as below:

If x is an integer, is 9^x + 9^(-x) = b?
(1) 3^x + 3^(-x) = √(b + 2)
(2) x > 0

Explanation:

(1) Square both sides of 3^x + 3^(-x) = √(b + 2)
3^(2x) + 3^(-2x) + 2[3^x * 3^(-x)] = b + 2
9^x + 9^(-x) + 2[3^(x - x)] = b + 2
9^x + 9^(-x) + 2[3^0] = b + 2
9^x + 9^(-x) + 2 = b + 2 (since 3^0 = 1)
So, 9^x + 9^(-x) = b; SUFFICIENT.

(2) x > 0 does not give us any information about b, so statement 2 is NOT sufficient.

The correct answer is A.
Anurag Mairal, Ph.D., MBA
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