BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Geometry

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Problem Solving |
User avatar
Legendary Member
Posts: 626
Joined: Fri Dec 23, 2011 2:50 amFollowed by: 10 members
Location: Ahmedabad
Thanked: 31 times

by ronnie1985 » Tue Jun 19, 2012 8:34 pm
Angle subtended by arcs are equal.

Angle OQP = Angle ORP = 35 degree

Angle subtended by the arc at the centre is twice the angle made by the intersecting chords.

=>The angle subtended at centre is 70 degree. Since the diameter and other chord are parallel, and if C is the centre of the circle, angle PCO = angle QCR = 70 degree

Hence angle subtended by arc PQ = angle PCQ = 360-70-70-180 = 40

Length of arc = (40/360)*2*pi*9 = 2*pi (A) is the answer.
Follow your passion, Success as perceived by others shall follow you
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pmFollowed by: 1906 members
Location: New York, NY
Thanked: 13060 times
GMAT Score:790

by GMATGuruNY » Wed Jun 20, 2012 3:31 am
Image

Since PQ||OR, angle QPR = angle PRO = 35.

An INSCRIBED ANGLE is formed by two chords.
Angles PRO and QPR are inscribed angles.
The degree measurement of an ARC intercepted by an inscribed angle is TWICE the degree measurement of the inscribed angle.
Thus, arc OP = 70° and arc QR = 70°, implying that arc PQ = 40°.

(Degree measurement of arc)/360 = (length of arc)/circumference

Since d=18, we get:
40/360 = PQ/(18Ï€)
(1/9)(18Ï€) = PQ
PQ = 2Ï€.

The correct answer is A.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 67
Joined: Mon May 03, 2010 12:03 pm
Thanked: 3 times

by myfish » Thu Jun 21, 2012 8:25 pm
[quote="GMATGuruNY"][url=https://postimage.org/image/922nn5aij/][img]https://s9.postimage.org/922nn5aij/inscribed_35_2.jpg[/img][/url]

Since PQ||OR, angle QPR = angle PRO = 35.

An INSCRIBED ANGLE is formed by two chords.
Angles PRO and QPR are inscribed angles.
The degree measurement of an ARC intercepted by an inscribed angle is TWICE the degree measurement of the inscribed angle.

THIS IS UNCLEAR TO ME. HOW CAN THE ANGLE CHANGE? 35degree is 35degree. Where do the 70degree come from? Why? Thanks so much!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pmFollowed by: 1906 members
Location: New York, NY
Thanked: 13060 times
GMAT Score:790

by GMATGuruNY » Fri Jun 22, 2012 10:01 am
myfish wrote:
GMATGuruNY wrote:Image

Since PQ||OR, angle QPR = angle PRO = 35.

An INSCRIBED ANGLE is formed by two chords.
Angles PRO and QPR are inscribed angles.
The degree measurement of an ARC intercepted by an inscribed angle is TWICE the degree measurement of the inscribed angle.

THIS IS UNCLEAR TO ME. HOW CAN THE ANGLE CHANGE? 35degree is 35degree. Where do the 70degree come from? Why? Thanks so much!
Perhaps my post here will help:

https://www.beatthegmat.com/grockit-circ ... 92556.html
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pmFollowed by: 1268 members
Location: Vancouver, BC
Thanked: 5254 times
GMAT Score:770

by Brent@GMATPrepNow » Fri Jun 22, 2012 11:55 am
Here's my solution:
Image

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1