If two cards are drawn at random from a deck of 52 cards

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emdadul28: Junior | Next Rank: 30 Posts; Posts: 10; Joined: Wed Nov 09, 2016 10:48 pm

If two cards are drawn at random from a deck of 52 cards

by emdadul28 » Mon Apr 17, 2017 12:15 pm

If two cards are drawn at random from a deck of 52 cards, what is the probability that both the cards will be form the same suit?

a. 1/13 b. 2/51 c. 3/17 d. None of these

ans: d.

If 4y -3x = 5, what is the smallest integer value of x for which y > 100?

a. 130
b. 131
c. 132
d. 395

ans: c

can you explain why?

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Source: Beat The GMAT — Problem Solving | Mon Apr 17, 2017 12:15 pm

DavidG@VeritasPrep: Legendary Member; Posts: 2663; Joined: Wed Jan 14, 2015 8:25 am; Location: Boston, MA; Thanked: 1153 times; Followed by:128 members; GMAT Score:770

by DavidG@VeritasPrep » Mon Apr 17, 2017 12:28 pm

emdadul28 wrote:If two cards are drawn at random from a deck of 52 cards, what is the probability that both the cards will be form the same suit?

a. 1/13
b. 2/51
c. 3/17
d. None of these

ans: d.

can you explain why?

We know that there are four suits and that each suit contains 13 cards. That first pick can be anything. We just need the second pick to match. So say the first pick is a heart. There will be 12 hearts remaining and 51 total cards remaining, so the probability that the next selection is a heart would be 12/51 or 4/17.

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[email protected]: Elite Legendary Member; Posts: 10392; Joined: Sun Jun 23, 2013 6:38 pm; Location: Palo Alto, CA; Thanked: 2867 times; Followed by:511 members; GMAT Score:800

by [email protected] » Mon Apr 17, 2017 5:43 pm

Hi emdadul28,

Are you actually studying for the GMAT? I ask because you've posted a number of questions that are not valid examples of GMAT Quant questions. If you are studying for the GMAT, then you should probably invest in more relevant testing materials. If you're not studying for the GMAT, then you should not be posting questions here that are not relevant to other GMAT Test Takers.

GMAT assassins aren't born, they're made,
Rich

Contact Rich at [email protected]