BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
Vote for Target Test Prep, Newsweek Readers’ Choice Awards 2026
NEWSWEEK READERS’ CHOICE 2026

BIG NEWS! Target Test Prep has been nominated, and they’d love your vote!

TTP has worked incredibly hard to build the best test prep experience possible, and winning Newsweek’s 2026 Readers’ Choice Award for Best Test Prep would mean a lot to them. If TTP has helped you, they’d be incredibly grateful for your vote. You can vote once each day through September 9.

Vote for TTP
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Ratio Problem.......GMATPrep

Expert replies
by Mo2men » Sun Apr 16, 2017 3:54 am
The ratio of boys to girls in Class A is 1 to 4, and that in Class B is 2 to 5. In addition, there are twice as many students in Class A as in Class B. If the two classes are combined to form one class, what would the resulting ratio of boys to girls?

A) 1 to 3
B) 5 to 12
C) 8 to 27
D) 6 to 25
E) 13 to 27

OA: C


Boys in class A = 1/5

Boys in Class B = 2/7

Let total boys in class A & B= X

1/5.....X.........2/7

I could not continue

How to use alligation method to solve problem above?
Join the discussion
Source: — Problem Solving |

by GMATGuruNY » Sun Apr 16, 2017 6:41 am
Mo2men wrote:The ratio of boys to girls in Class A is 1 to 4, and that in Class B is 2 to 5. In addition, there are twice as many students in Class A as in Class B. If the two classes are combined to form one class, what would the resulting ratio of boys to girls?

A) 1 to 3
B) 5 to 12
C) 8 to 27
D) 6 to 25
E) 13 to 27
Let M = the mixture of the two classes.
Alligation can be performed only with percentages or fractions.

Step 1: Convert the ratios to FRACTIONS.
A:
Since boys/girls = 1/4, and 1+4=5, boys/total = 1/5.
B:
Since boys/girls = 2/5, and 2+5=7, boys/total = 2/7.

Step 2: Put the fractions over a COMMON DENOMINATOR.
A = 1/5 = 7/35.
B = 2/7 = 10/35.

Step 3: Plot the fractions on a number line, with A and B on the ends and M in the middle.
A 7/35-----------M-----------10/35 B

Step 4: Calculate the distances between A, M and B.
This distances on the number of line are determined by the RECIPROCAL of the following ratio:
(number of students in A)/(number of students in B).
Since A has twice as many students as B, A/B = 2x/x.
Plotting the reciprocal of this ratio on the number line, we get:
A 7/35----x----M----2x----10/35 B

Step 5: Determine the value of x.
The number line indicates that the total distance (x+2x) is equal to the difference between 10/35 and 7/35:
x+2x = 10/35 - 7/35
3x = 3/35
x = 1/35.

Thus:
boys/total in M = 7/35 + x = 7/35 + 1/35 = 8/35.
Implication:
Of every 35 students in M, 8 are boys, implying that the remaining 27 students are girls.
Thus:
boys/girls in M = 8/27.

The correct answer is C.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Join the discussion

by Brent@GMATPrepNow » Sun Apr 16, 2017 7:02 am
Mo2men wrote:The ratio of boys to girls in Class A is 1 to 4, and that in Class B is 2 to 5. In addition, there are twice as many students in Class A as in Class B. If the two classes are combined to form one class, what would the resulting ratio of boys to girls?

A) 1 to 3
B) 5 to 12
C) 8 to 27
D) 6 to 25
E) 13 to 27
We can also solve the question using weighted averages.

Weighted average of groups combined = (group A proportion)(group A average) + (group B proportion)(group B average) + (group C proportion)(group C average) + ...

So, in this case, Weighted average of combined classes = (Class A proportion)(Class A average) + (Class B proportion)(Class B average)

CLASS A:
Ratio of boys to girls in Class A is 1 to 4
So, for every 5 students, we have 1 boy and 4 girls.
In other words, 1/5 of the students are boys.
So, we can say the class A average is 1/5 boys

CLASS B:
Ratio of boys to girls in Class B is 2 to 5
So, for every 7 students, we have 2 boys and 5 girls.
In other words, 2/7 of the students are boys.
So, we can say the class B average is 2/7 boys

There are twice as many students in Class A as in Class B.
So, for every 3 students in the COMBINED group, there are 2 students from Class A, and 1 student from Class B
In others words, Class A students comprise 2/3 of the COMBINED group, and Class B students comprise 1/3 of the COMBINED group

Now plug these values into our formula to get:
Weighted average of combined classes = (2/3)(1/5) + (1/3)(2/7)
= 2/15 + 2/21
= 14/105 + 10/105
= 24/105
= 8/35

So, in the combined group, 8/35 of the students are boys, which means 27/35 of the students are girls.
In other words, among every 35 students in the combined group, 8 are boys and 27 are girls.
So, the ratio of boys to girls = 8 to 27

Answer: C

For more information on weighted averages, you can watch this video: https://www.gmatprepnow.com/module/gmat- ... ics?id=805

Here are some additional practice questions related to weighted averages:
- https://www.beatthegmat.com/weighted-ave ... 17237.html
- https://www.beatthegmat.com/weighted-ave ... 14506.html
- https://www.beatthegmat.com/average-weig ... 57853.html
- https://www.beatthegmat.com/averages-que ... 87118.html

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion

by [email protected] » Sun Apr 16, 2017 11:23 am
Hi Mo2men,

This question can be solved by TESTing VALUES. Before choose your values though, you have to note the ratios involved:

1) Class A has a ratio of boys:girls = 1:4. This means that there are 4 girls for every 1 boy (and that the total number of girls MUST be a multiple of 4 and the total number of students MUST be a multiple of 5).
2) Class B has a ratio of boys:girls = 2:5. This means that there are 5 girls for every 2 boys (and that the total number of boys MUST be a multiple of 2, the total number of girls MUST be a multiple of 5 and the total number of students MUST be a multiple of 7).

We're told that the total number of students in Class A is TWICE the total number of students in Class B. Thus, we need to TEST a multiple of 5 that is exactly TWICE a multiple of 7...

Let's TEST
Class A = 70 students (14 boys and 56 girls)
Class B = 35 students (10 boys and 25 girls)

By combining these two classes, we'll end up with 24 boys and 81 girls, giving us a ratio of 24:81. Since 24 and 81 are both multiples of 3, we can reduce this ratio to... 8:27

Final Answer: C

GMAT assassins aren't born, they're made,
Rich
Contact Rich at [email protected]
Image
Join the discussion

by Jay@ManhattanReview » Sun Apr 16, 2017 10:44 pm
Mo2men wrote:The ratio of boys to girls in Class A is 1 to 4, and that in Class B is 2 to 5. In addition, there are twice as many students in Class A as in Class B. If the two classes are combined to form one class, what would the resulting ratio of boys to girls?

A) 1 to 3
B) 5 to 12
C) 8 to 27
D) 6 to 25
E) 13 to 27

OA: C


Boys in class A = 1/5

Boys in Class B = 2/7

Let total boys in class A & B= X

1/5.....X.........2/7

I could not continue

How to use alligation method to solve problem above?
Hi Mo2men,

A couple of nice approaches by experts... Here's my way.

On a ratio scale, the total number of students in the Class A = 1 + 4 = 5;

Similarly, on a ratio scale, the total number of students in the Class B = 2 + 5 = 7;

Say the total number of students in Class A = 5x and that in Class B = 7; where x is a constant of proportionality

We are given that the number of students in Class A = 2*the number of students in Class B

=> 5x = 2*7

=> x = 14/5

Ratio of total number of boys in both the classes to total number of girls in both the classes

=> [{(14/5)*1} + 2] : [{(14/5)*4} + 5]

=> (14/5 + 2) : (56/5 + 5)

=> 24 : 81

=>[spoiler] 8 : 27[/spoiler]

The correct answer: C

Hope this helps!

Relevant book: Manhattan Review GMAT Math Essentials Guide

-Jay
_________________
Manhattan Review GMAT Prep

Locations: New York | Frankfurt | Hong Kong | Zurich | and many more...

Schedule your free consultation with an experienced GMAT Prep Advisor! Click here.
Join the discussion

by GMATGuruNY » Tue Apr 18, 2017 4:49 am
Mo2men wrote:The ratio of boys to girls in Class A is 1 to 4, and that in Class B is 2 to 5. In addition, there are twice as many students in Class A as in Class B. If the two classes are combined to form one class, what would the resulting ratio of boys to girls?

A) 1 to 3
B) 5 to 12
C) 8 to 27
D) 6 to 25
E) 13 to 27
In A, boys/total = 1/5 = 7/35.
In B, boys/total = 2/7 = 10/35.

Since A has twice as many students as B, let A = 70 students and B = 35 students.

A:
Since boys constitute 1/5 of the total, boys = (1/5)(70) = 14, with the result that girls = 70-14 = 56.
B:
Since boys constitute 2/7 of the total, boys = (2/7)(35) = 10, with the result that girls = 35-10 = 25.
Resulting ratio for A+B:
(boys in A + boys in B)/(girls in A + girls in B) = (14+10)/(56+25) = 24/81 = 8/27.

The correct answer is C.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Join the discussion