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$$Is\ a\ +\ a^{-1}\ >\ 2\ ?$$
(1) a > 0
(2) a < 1
(1) a > 0
(2) a < 1
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The error is highlighted above in blue.harsh8686 wrote:Can anyone please tell me what wrong with my approach:
=> the given equation can be written as a + 1/a > 2
=> (a^2+ 1)/a > 2
=> (a^2 + 1 - 2a)/a > 0
=> (a-1)^2/a > 0
since (a-1)^2 will always be positive therefore if a>0 we will have the answer as YES, and if a<0 then the answer is NO
STATEMENT 1
(1) a>0: SUFFICIENT
STATEMENT 2
(2) a<1: INSUFFICIENT
However, the official answer is C
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