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GMAT Math Question Help Please

Expert replies
by phoenix9801 » Thu Jan 14, 2010 8:33 pm
1-
In a certain school, 50 percent of all male students and 60 percent of all female students play a varsity sport. If 40 percent of the students at the school are male, what percent of the students DO NOT play a varsity sport?

2-
The average (arithmetic mean) of 6 positive numbers is 5. If the average of the least and greatest of these numbers is 7, what is the average of the 4 other numbers?


3-
Poplar trees are planted on both sides of a straight street that is of a kilometer in length. Each tree is planted in a plot that is 1 meter in length, and there are 16 meters of space between adjacent plots on the same side of the street. What is the maximum number of poplar trees lining the street?


4-
Which of the following equations is NOT equivalent to 16a2 = b2 - 9?

a- 16a2 + 9 = b2
b- 64a2 = 4b2 - 36
c- 16a2 = (b + 3)(b - 3)
d- 4a = b - 3
e- a^2 = b^2 - 9 / 16
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Source: — Problem Solving |

by ace_gre » Fri Jan 15, 2010 10:55 am
Hi here is my take on the problems..

1-
Lets say number of male students = 100.
Then 50 of the male students play varsity sport.
Let number of students in college be s. Then 0.4s = male =100
s=100/0.4= 250.
Total female students = 0.6*250 = 150
Female students who play varsity sports = 0.6*150=90.

Total students who do not play varsity sports = 250-100-90=60

Percentage = 60/250 =24%

2-
Sum of 6 numbers = average *6 = 30
Sum of greatest and least = 7*2 = 14
Sum of remaining 4 numbers = 30-14=16
Average of the remaining 4 numbers = 16/4 =4

3-
1 km =1000m
2 trees can be planted in 18m(1tree+space+1tree)
? trees can be planted in 1000m
~111 trees per side.

Total # of trees =111*2=222

4-
(4a)^2 = (b+3)(b-3)
All the options can be rearranged except d which is not the same as above.
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