If $$x+y^2=(x+y^2)^2,$$VJesus12 wrote:If $$x+y^2=(x+y^2)^2,$$ what is the value of y?
(1) x = y ^2
(2) xy ^2 = 0
The OA is C.
I don't understand why is not sufficient the statement (1). Experts, may you give me some help here, please? Thanks.
then x+y^2 = 1 or 0
Question : y = ?
Statement 1: x = y ^2
@x+y^2 = 1, y ^2 = 1/2 i.e. y = 1/√2
@x+y^2 = 0, y ^2 = 0 i.e. y = 0
NOT SUFFICIENT
Statement 2: x*y ^2 = 0
@x+y^2 = 1, y ^2 = 0 or y^2=1 i.e. y = 0 or 1
NOT SUFFICIENT
Combining the two statements
x = y ^2 and x*y ^2 =
i.e. x = y = 0
SUFFICIENT
Answer: Option C
