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The formula for 3 intersecting sets is Total=A+B+C−(AUB+AUC+BUC)+AnBnC + Neither
While solving some questions I came across the formula : Total = A + B + C - (sum of 2-group overlaps) - 2*(all three) + Neither
Is this correct? When 2 group overlaps are considered, aren't we substracting the all 3 intersection area already? $$$$
While solving some questions I came across the formula : Total = A + B + C - (sum of 2-group overlaps) - 2*(all three) + Neither
Is this correct? When 2 group overlaps are considered, aren't we substracting the all 3 intersection area already? $$$$
















