BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

OG: Carol purchased one basket of fruit consisting of 4 apples and 2 oranges

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Master | Next Rank: 500 Posts
Posts: 394
Joined: Sun Jul 02, 2017 10:59 am
Thanked: 1 times
Followed by:5 members

OG: Carol purchased one basket of fruit consisting of 4 apples and 2 oranges

by AbeNeedsAnswers » Tue May 19, 2020 7:08 pm

Timer

00:00

Your Answer

A

B

C

D

E

Global Stats

Carol purchased one basket of fruit consisting of 4 apples and 2 oranges and another basket of fruit consisting of 3 apples and 5 oranges. Carol is to select one piece of fruit at random from each of the two baskets. What is the possibility that one of the two pieces of fruit selected will be an apple and the other will be an orange?

A. 1/4
B. 1/2
C. 1/24
D. 5/24
E. 13/24

E
Top
Source: — Problem Solving |

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pm
Location: Vancouver, BC
Thanked: 5254 times
Followed by:1268 members
GMAT Score:770

Re: OG: Carol purchased one basket of fruit consisting of 4 apples and 2 oranges

by Brent@GMATPrepNow » Wed May 20, 2020 5:41 am
AbeNeedsAnswers wrote: ↑
Tue May 19, 2020 7:08 pm
 Carol purchased one basket of fruit consisting of 4 apples and 2 oranges and another basket of fruit consisting of 3 apples and 5 oranges. Carol is to select one piece of fruit at random from each of the two baskets. What is the possibility that one of the two pieces of fruit selected will be an apple and the other will be an orange?

A. 1/4
B. 1/2
C. 1/24
D. 5/24
E. 13/24

E
Let's name the baskets!
Basket A has 4 Apples and 2 Oranges
Basket B has 3 Apples and 5 Oranges

P(1 of each type) = P(select apple from basket A AND orange from basket B OR select orange from basket A AND apple from basket B)
= [P(apple from basket A) x P(orange from basket B)] + [P(orange from basket A) x P(apple from basket B)]
= [4/6 x 5/8] + [2/6 x 3/8]
= 20/48 + 6/48
= 26/48
= 13/24

Answer: E

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Top

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 8083
Joined: Sat Apr 25, 2015 10:56 am
Location: Los Angeles, CA
Thanked: 43 times
Followed by:29 members

Re: OG: Carol purchased one basket of fruit consisting of 4 apples and 2 oranges

by Scott@TargetTestPrep » Sun May 24, 2020 6:02 am
AbeNeedsAnswers wrote: ↑
Tue May 19, 2020 7:08 pm
 Carol purchased one basket of fruit consisting of 4 apples and 2 oranges and another basket of fruit consisting of 3 apples and 5 oranges. Carol is to select one piece of fruit at random from each of the two baskets. What is the possibility that one of the two pieces of fruit selected will be an apple and the other will be an orange?

A. 1/4
B. 1/2
C. 1/24
D. 5/24
E. 13/24

E
The probability of selecting an orange from the first basket and an apple from the second basket is:

2/6 x 3/8 = 1/3 x 3/8 = 3/24

The probability of selecting an apple from the first basket and an orange from the second basket is:

4/6 x 5/8 = 2/3 x 5/8 = 10/24

Thus, the overall probability is 3/24 + 10/24 = 13/24.

Answer: E

Scott Woodbury-Stewart
Founder and CEO
[email protected]

Image

See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews

ImageImage
Top
Newbie | Next Rank: 10 Posts
Posts: 1
Joined: Mon Jul 27, 2020 12:27 am

Re: OG: Carol purchased one basket of fruit consisting of 4 apples and 2 oranges

by pyaasa » Mon Aug 10, 2020 9:37 am
Basket 1 - 4 A, 2 O; Basket 2- 3 A, 5 O
Probability = No of fav outcomes/Total no of outcomes
Fav Outcomes = 4C1*5C1+2C1*3C1 (Selecting 1 A &(AND 1O from B1 OR 1 O & 1 A from B2)


AND means multiplication and OR means addition

Total outcomes - 6C1*8C1 (Selecting 1 item from B1 AND Selecting one item from B2 - Question mentions that 1 item is picked from either basket at a time)

Probablity =20+6/48=26/48=13/24
Top
Post new topic Post Reply
• Page 1 of 1