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The points \(A(0, 0), B(0, 4a - 5)\) and \(C(2a + 1, 2a + 6)\) form a triangle. If angle \(ABC = 90^{\circ},\) what is

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The points \(A(0, 0), B(0, 4a - 5)\) and \(C(2a + 1, 2a + 6)\) form a triangle. If angle \(ABC = 90^{\circ},\) what is

by Gmat_mission » Sun Nov 07, 2021 1:11 pm

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The points \(A(0, 0), B(0, 4a - 5)\) and \(C(2a + 1, 2a + 6)\) form a triangle. If angle \(ABC = 90^{\circ},\) what is the area of triangle \(ABC?\)

A. 102
B. 120
C. 132
D. 144
E. 256

Answer: A

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