What is the area of circle passing points A, B & C...

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by [email protected] » Fri Dec 06, 2013 4:05 pm
Hi Zach,

I think that we'd need whatever information is included in the picture to answer this question.

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by Zach.J.Dragone » Fri Dec 06, 2013 5:46 pm
Sorry, I forgot to attach it!
[email protected] wrote:Hi Zach,

I think that we'd need whatever information is included in the picture to answer this question.

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by theCodeToGMAT » Sat Dec 07, 2013 2:44 am
Answer [spoiler]{E}[/spoiler]
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by Uva@90 » Sat Dec 07, 2013 5:29 am
theCodeToGMAT wrote:Answer [spoiler]{E}[/spoiler]
Rahul,
in this question, if statement 1 is re-phrased as "Angle BOC is 120"
Then answer is C right ?

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by theCodeToGMAT » Sat Dec 07, 2013 5:39 am
Uva@90 wrote:
theCodeToGMAT wrote:Answer [spoiler]{E}[/spoiler]
Rahul,
in this question, if statement 1 is re-phrased as "Angle BOC is 120"
Then answer is C right ?

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Uva.
Yep, then it must be [spoiler]{C}[/spoiler]
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by Zach.J.Dragone » Sat Dec 07, 2013 11:31 am
But if BOC is 120 and the inscribed angle is 60 then isn't O the center of the circle?

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by theCodeToGMAT » Sat Dec 07, 2013 11:47 am
Zach.J.Dragone wrote:But if BOC is 120 and the inscribed angle is 60 then isn't O the center of the circle?
In that case yes...but the question says:

(1) Angle AOC is 120.
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by Mathsbuddy » Sat Dec 07, 2013 1:26 pm
theCodeToGMAT wrote:
Zach.J.Dragone wrote:But if BOC is 120 and the inscribed angle is 60 then isn't O the center of the circle?
In that case yes...but the question says:

(1) Angle AOC is 120.
True, we know that if O is the centre, then by circle theory, AOC = BOC = AOB = 120 and the triangles so formed are isosceles. If we then try to move O to a different place, then it is impossible to do so without AOC changing to something different to 120. Therefore, surely AOC = 120 and O is the centre... What do you think...

On second thoughts, I see that this is not necessarily the case, so you are 100 percent right!
Last edited by Mathsbuddy on Sat Dec 07, 2013 1:41 pm, edited 1 time in total.

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by GMATGuruNY » Sat Dec 07, 2013 1:30 pm
I believe that the figure should look as shown below:
Zach.J.Dragone wrote:What is the area of circle passing points A, B & C (in the given figure), if the angle ABC is 60?

(1) Angle AOC is 120.
(2) OA is 6 units.

Image
E
Statements combined:
It is possible to draw a circle through ANY 3 POINTS.
Draw a circle through points A, O and C:
Image
In the blue circle above, any inscribed angle that intercepts the blue circle at points A and C will have a degree measurement of 120.
In the figure above, ∠AO�C and ∠AO₂C each have a degree measurement of 120.
Thus, while it is POSSIBLE that O is the center of the circle, it is also possible that O is NOT the center of the circle.
If O is the center, then OA = r = 6, with the result that the area = 36Ï€.
If O is NOT the center, then the radius and the area cannot be determined.
INSUFFICIENT.

The correct answer is E.
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by Mathsbuddy » Sat Dec 07, 2013 1:39 pm
(1) Angle AOC is 120 - insufficient as no dimensions are given.
(2) OA is 6 units - insufficient as we don't know if O is the centre.

Combined, this could be true: AOC = BOC = AOB = 120 because the sum of 360 can only occur if BOC = 120, and O is the centre (by circle theory 2*BAC = BOC with O at the centre): Area = 36pi.

However, O could be off-centre and all other values still hold true. Therefore the information is insufficient.