Would appreciate your help with this one:
What is the sum of all remainders obtained when the first 100 natural numbers are divided by 9?
A. 397
B. 401
C. 403
D. 405
E. 399
Tried to solve many times in many ways but I never get any of these answers.
What is the sum of all remainders obtained when the first 100 natural numbers are divided by 9?
A. 397
B. 401
C. 403
D. 405
E. 399
Tried to solve many times in many ways but I never get any of these answers.

















