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Given that a is the average (arithmetic mean) of the first nine positive multiples of six and b is the median of the

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Given that a is the average (arithmetic mean) of the first nine positive multiples of six and b is the median of the

by BTGmoderatorDC » Fri Oct 23, 2020 4:41 pm

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Given that a is the average (arithmetic mean) of the first nine positive multiples of six and b is the median of the first twelve positive multiples of six, what is the ratio of a to b?

A. 3:4
B. 10:13
C. 5:6
D. 13:10
E. 4:3


OA B

Source: Manhattan Prep
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