- akhilsuhag
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Geometry- GMATprep1
This topic has expert replies
Source: Beat The GMAT — Problem Solving |
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thestartupguy
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from observation you know that arc OP will equal arc QR. If we can find those length we can subtract them from half of the circumference and find the arc PQ
so arc OP = 2(pi)(9)(70/360)=7/2 (pi) double the 35
arc OP+arc QR = 2 arc OP= 14/2 (pi)=7 pi
half the circumference of the entire circle is (180/360)*2*(pi)*9=9(pi)
arc PQ = 9(pi)-7(pi) = [spoiler]A 2 (pi)[/spoiler]
so arc OP = 2(pi)(9)(70/360)=7/2 (pi) double the 35
arc OP+arc QR = 2 arc OP= 14/2 (pi)=7 pi
half the circumference of the entire circle is (180/360)*2*(pi)*9=9(pi)
arc PQ = 9(pi)-7(pi) = [spoiler]A 2 (pi)[/spoiler]













