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Rhonda runs at an average speed of 12 kilometers per hour, and she bicycles

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Rhonda runs at an average speed of 12 kilometers per hour, and she bicycles

by BTGModeratorVI » Fri Jul 03, 2020 6:55 am

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Rhonda runs at an average speed of 12 kilometers per hour, and she bicycles at an average speed of 30 kilometers per hour. When she bicycles to work, her travel time is 2.25 minutes less than when she runs to work. The distance to work, in kilometers, is

A) 27/40
B) 3/4
C) 7/8
D) 11/12
E) 6/5

Answer: B
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Re: Rhonda runs at an average speed of 12 kilometers per hour, and she bicycles

by ssrivastava » Sat Jul 04, 2020 3:10 am
Let distance be x then

2.25/60+x/30 = x/12
solving for X,
x=3/4 km

Ans B
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Re: Rhonda runs at an average speed of 12 kilometers per hour, and she bicycles

by Brent@GMATPrepNow » Sat Jul 04, 2020 5:52 am
BTGModeratorVI wrote: ↑
Fri Jul 03, 2020 6:55 am
 Rhonda runs at an average speed of 12 kilometers per hour, and she bicycles at an average speed of 30 kilometers per hour. When she bicycles to work, her travel time is 2.25 minutes less than when she runs to work. The distance to work, in kilometers, is

A) 27/40
B) 3/4
C) 7/8
D) 11/12
E) 6/5

Answer: B
Source: GMAT Prep Now
When Rhonda bicycles to work, her travel time is 2.25 minutes less than when she runs to work
It might be useful to start with a "Word Equation"
(Rhonda's running time in hours) = (Rhonda's cycling time in hours) + 2.25/60
Aside: 2.25 minutes = 2.25/60 hours

travel time = distance/speed
We know the running and cycling speeds, but we don't know the distance.
So, let d = distance to work

So, we get: d/12 = d/30 + 2.25/60
To eliminate the fractions, multiply both sides by 60 (the LCM of 12, 30 and 60)
We get: 5d = 2d + 2.25
Subtract 2d from both sides: 3d = 2.25
Solve: d = 2.25/3
Check answer choices . . . not there.

Looks like we need to rewrite 2.25/3 as an equivalent fraction.
If we take 2.25/3, and multiply top and bottom by 4 we get: 9/12, which is the same as 3/4

Answer: B
Brent Hanneson - Creator of GMATPrepNow.com
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