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Source: — Data Sufficiency |
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by Frankenstein » Thu Jun 02, 2011 5:36 am
Hi,
Assuming X!=3 as 'x not equal to' 3[Programming language representation], I will solve this.Because x factorial=3 really doesn't make sense.
sqt(x-3)^2 = |x-3|
|x-3| = x-3, if x>=3
|x-3| = 3-x, if x<=3
From(1): x not equal to 3, we don't know if x>3 or not
Insufficient
From(2): -x|x|>0. As |x|>=0, -x>0 =>x<0
if x<0, then definitely x<3. So, |x-3|=3-x
Sufficient

Hence, B
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by cans » Thu Jun 02, 2011 5:46 am
sqt(x-3)^2 = 3-x?
a)x!=3
l.h.s. can be x-3 when x>3 or 3-x when x<3. Thus insufficient.
b) -x|x|>0
it means x is not equal to 0 and as |x|>0,
-x>0 => x<0
as x<0, sqt(x-3)^2 = 3-x.Always true
IMO B
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