BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

OG In the multiplication table above, each letter

Expert replies
by AbeNeedsAnswers » Sat Aug 19, 2017 2:59 pm

Timer

00:00

Answers

A

B

C

D

E

Stats

Difficulty

Image

In the multiplication table above, each letter represents an integer. What is the value of c?

(1) c = f
(2) h not= 0

E
Join the discussion
Source: — Data Sufficiency |

by Scott@TargetTestPrep » Fri Nov 17, 2017 11:53 am
AbeNeedsAnswers wrote:Image

In the multiplication table above, each letter represents an integer. What is the value of c?

(1) c = f
(2) h not= 0
We need to determine the value of c. Following our table, we have:

a x c = f

b x c = h

and

c^2 = j

Statement One Alone:

c = f

Since c = f, we have:

a x c = c

ac - c = 0

c(a - 1) = 0

c = 0 or a = 1

We see that either c = 0 or a = 1 (if c ≠ 0). Since we don't know whether c is 0, we cannot determine the value of c. Statement one alone is not sufficient to answer the question.

Statement Two Alone:

h ≠ 0

Since h is not zero, neither b nor c is zero. However, we still can't determine the value of c. Statement two alone is not sufficient to answer the question.

Statements One and Two Together:

Using statement two, we know that c ≠ 0, and thus from statement one, a = 1. However, c can be any nonzero number, so we still cannot determine a value for c.

Answer: E

Scott Woodbury-Stewart
Founder and CEO
[email protected]

Image

See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews

ImageImage
Join the discussion

by [email protected] » Wed Apr 04, 2018 7:50 pm
Hi All,

We're told that in the multiplication table above, each letter represents an INTEGER. We're asked for the value of C. While this question might look 'complex', it's actually based on some really low-level Arithmetic (specifically multiplication) and can be solved with a little note-taking and logic.

To start, it's important to define what the information in the table really means. Since it's a MULTIPLICATION TABLE, we can deduce the following:
(A)(A) = D
(A)(B) = E
(A)(C) = F
(B)(B) = G
Etc.

1) C = F

Fact 1 tells us that C and F are the SAME integer. Since (A)(C) = F there are two possibilities to consider:
1) A = 1 and C and F are ANY integer.
2) C and F are both 0 and A is ANY integer
Unfortunately, we don't have enough information to figure out any of the values, so C could be ANY integer.
Fact 1 is INSUFFICIENT

2) H is NOT equal to 0.

Fact 2 tells us that H cannot equal 0. Since (B)(C) = H, this means that neither B nor C can equal 0 either. Unfortunately, we still don't have enough information to figure the value of C (we just know that it can't be 0).
Fact 2 is INSUFFICIENT

Combined, we know
Neither B, C nor H can equal 0
A = 1
Based on the deductions that we made in Fact 1, we know that C can be any integer - and with Fact 2, we know that C can't be 0. There's still an infinite number of possible values for C though.
Combined, INSUFFICIENT

Final Answer: E

GMAT assassins aren't born, they're made,
Rich
Contact Rich at [email protected]
Image
Join the discussion