I had a question hopefully someone can help me with.
if 2x (5n) = t, what is the value of t?
1) x = n+3
2) 2x = 32
I realize 1 and 2 by themselves are not sufficient which is obvious. But the approach I took gives me two solutions, making it answer choice E, but the official answer is C.
What i did:
1) x=n+3
10(n+3)n = t
10n^2 + 30n = t
N.S
2) 2x = 32
x=16
t=10(16)n = 160n
N.S
1+2)
10n^2 + 30n = t
t=160n from 2, so
10n^2 + 30n = 160n
10n^2 - 130n = 0
n^2 - 13n = 0
n(n-13) = 0
n = 0 or n = 13
since the problem suggests nothing about n being non zero or positive or negative, i took the two answers to mean this is NS and chose E.
Why is this wrong?
The actual answer is just 13 since 1) since x = n+3, and 2 gives x = 16, so n = 16-3 = 133 and thus C is correct answer. C seems a bit too obvious though, which is another reason I'm now thinking it seems even more obvious.
if 2x (5n) = t, what is the value of t?
1) x = n+3
2) 2x = 32
I realize 1 and 2 by themselves are not sufficient which is obvious. But the approach I took gives me two solutions, making it answer choice E, but the official answer is C.
What i did:
1) x=n+3
10(n+3)n = t
10n^2 + 30n = t
N.S
2) 2x = 32
x=16
t=10(16)n = 160n
N.S
1+2)
10n^2 + 30n = t
t=160n from 2, so
10n^2 + 30n = 160n
10n^2 - 130n = 0
n^2 - 13n = 0
n(n-13) = 0
n = 0 or n = 13
since the problem suggests nothing about n being non zero or positive or negative, i took the two answers to mean this is NS and chose E.
Why is this wrong?
The actual answer is just 13 since 1) since x = n+3, and 2 gives x = 16, so n = 16-3 = 133 and thus C is correct answer. C seems a bit too obvious though, which is another reason I'm now thinking it seems even more obvious.













