I am having trouble rephrasring this question ALGEBRAICALLY and solving
I understand, that Y will be greater than y^2 if y is a proper fraction i.e. 0<y<1
HOWEVER, I am UNABLE to simplify this ALGEBRAICALLY. Pls advise
Is y greater than y^2 ?
1) y is greater than -1.
2) y^2 is greater than 1.
Please tell me where I am going wrong with this
First rephrase the original inequality
y>y^2?
y^2 - y < 0 ?
Factoring out the common y
y(y-1)<0 ?
In order for this inequality to hold
either y<0 and y-1>0 or
(y-1) <0 and y > 0
this is b/c the two must have opposite signs
The first possibility simplified gives us
y<0 and y>1
The second possibility simplified gives us
y>0 and y<1
statement 1:
y > -1
this doesnt even tell us whether y>0 or y<0
insuff
statement 2
y^2>1
then, either y>1 or y<-1
OA is B
HOW DO YOU FIGURE OUT THE ANSWER TO THE REPHRASED QUESTION WITH THIS STATEMENT??
I understand, that Y will be greater than y^2 if y is a proper fraction i.e. 0<y<1
HOWEVER, I am UNABLE to simplify this ALGEBRAICALLY. Pls advise
Is y greater than y^2 ?
1) y is greater than -1.
2) y^2 is greater than 1.
Please tell me where I am going wrong with this
First rephrase the original inequality
y>y^2?
y^2 - y < 0 ?
Factoring out the common y
y(y-1)<0 ?
In order for this inequality to hold
either y<0 and y-1>0 or
(y-1) <0 and y > 0
this is b/c the two must have opposite signs
The first possibility simplified gives us
y<0 and y>1
The second possibility simplified gives us
y>0 and y<1
statement 1:
y > -1
this doesnt even tell us whether y>0 or y<0
insuff
statement 2
y^2>1
then, either y>1 or y<-1
OA is B
HOW DO YOU FIGURE OUT THE ANSWER TO THE REPHRASED QUESTION WITH THIS STATEMENT??












