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Sudoku DS problem from OG13

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by [email protected] » Sat Dec 15, 2012 9:32 am
Eachof the letters inthe table above represents one of the numbers 1, 2, or 3, and each of these numbers occurs exactly once ineach row and exactly once in each column. What is the value of r ?
(1) v + z = 6
(2) s + t + u + x = 6
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Source: — Data Sufficiency |

by [email protected] » Sat Dec 15, 2012 10:26 am
Sorry let me post the matrix here

r s t
u V w
X y 1

Imagine the matrix is 3x3 ( above)

103. Eachof the letters inthe table above represents one of the numbers 1, 2, or 3, and each of these numbers occurs exactly once ineach row and exactly once in each column. What is the value of r ?
(1) v + z = 6
(2) s + t + u + x = 6

From (1) we can get V=Z=3 ( Sufficient)
From (2) we can ger 1,1,1,3 or 1,1,2,2
Of these 1,1,1, is not possible since it would be mean that there is 1,1 in one column or row which is not possible according to the statement so my answer is D

The OG answer is A since it does not take into consideration 1,1,2,2 from (2) . I am not able to understand why OG is not even considering 1,1,2,2 ?
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by Brent@GMATPrepNow » Sat Dec 15, 2012 11:08 am
[email protected] wrote:
r s t
u V w
X y 1

Imagine the matrix is 3x3 ( above)

103. Eachof the letters inthe table above represents one of the numbers 1, 2, or 3, and each of these numbers occurs exactly once ineach row and exactly once in each column. What is the value of r ?
(1) v + z = 6
(2) s + t + u + x = 6

Statement 1:
Step 1: If v+z=6, then v and z must both equal 3.
Step 2: If each number occurs exactly once in each row and exactly once in each column, then s cannot equal 3 (since s and v are in the same column) and t cannot equal 3 (since t and z are in the same column).
Step 3: If s and t cannot equal 3, then r must equal 3 (since each number occurs exactly once in each row)
As such, statement 1 is SUFFICIENT

Statement 2:
If each number occurs exactly once in each row and exactly once in each column, the sum of numbers in any row or column will always equal 6.
So, r+s+t=6, and r+u+x=6
When we combine these two equations, we get
(r+s+t)+ (r+u+x)= 6+6
Simplify to get: 2r+(s+t+u+x)=12
Statement 2 tells us that s+t+u+x=6
When we add this to the equation 2r+(s+t+u+x)=12, we get: 2r+(6)=12
When we solve this, we get r=3
As such, statement 2 is SUFFICIENT

Answer = D

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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