values in set S

This topic has expert replies
Legendary Member
Posts: 510
Joined: Thu Aug 07, 2014 2:24 am
Thanked: 3 times
Followed by:5 members

values in set S

by j_shreyans » Mon Jun 08, 2015 7:40 am
Set S contains seven distinct integers. The median of set S is the integer m, and all values in set S are equal to or less than 2m. What is the highest possible average (arithmetic mean) of all values in set S ?

A)m
B)10m/7
C)10m/7 - 9/7
D)5m/7 + 3/7
E)5m


OA C
Source: — Problem Solving |

User avatar
Master | Next Rank: 500 Posts
Posts: 154
Joined: Wed May 21, 2014 4:29 am
Thanked: 8 times
Followed by:1 members

by talaangoshtari » Mon Jun 08, 2015 8:15 am
Assume set S is
S={1, 2, 3, 4, 5, 6, 7}
m=4 and since S is evenly spaced, mean is equal to the median.
Now, since we should maximazie the mean, we can replace the 3 numbers that are larger than the median with bigger numbers. So, we replace 5 with 6, 6 with 7 and 7 with 8. Now the mean is equal to 31/7. Plug in m=4 and search for the answer choice that is equal to 31/7. Answer choice C is equal to 31/7, so it is the correct answer.

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pm
Location: Vancouver, BC
Thanked: 5254 times
Followed by:1268 members
GMAT Score:770

by Brent@GMATPrepNow » Mon Jun 08, 2015 8:15 am
Set S contains seven distinct integers. The median of set S is the integer m, and all values in set S are equal to or less than 2m. What is the highest possible average (arithmetic mean) of all values in set S ?

A)m
B)10m/7
C)10m/7 - 9/7
D)5m/7 + 3/7
E)5m
One approach is to TEST a value of m.

Let's say m = 5.
So, when we arrange all 7 values in ASCENDING order, 5 is the MEDIAN: _ _ _ 5 _ _ _
Since all values in set S are equal to or less than 2m, the BIGGEST value is 10.
So, we get: _ _ _ 5 _ _ 10
At this point, we are tying to MAXIMIZE the other values AND make sure all are DISTINCT.
So, we get: 2, 3, 4, 5, 8, 9, 10
The average = (2 + 3 + 4 + 5 + 8 + 9 + 10)/7 = 41/7

Now plug m = 5 into the answer choices to see which one yields an average of 41/7

A) 5 NOPE
B) 10m/7. So, we get: 10(5)/7 = 50/7 NOPE
C) 10m/7 - 9/7. So, we get: 10(5)/7 - 9/7 = 41/7 BINGO!!
D) 5m/7 + 3/7. So, we get: 5(5)/7 + 3/7 = 28/7 NOPE
E) 5m. So, we get: 5(5) = 25 NOPE

Answer: C

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pm
Location: Vancouver, BC
Thanked: 5254 times
Followed by:1268 members
GMAT Score:770

by Brent@GMATPrepNow » Mon Jun 08, 2015 8:16 am
Set S contains seven distinct integers. The median of set S is the integer m, and all values in set S are equal to or less than 2m. What is the highest possible average (arithmetic mean) of all values in set S ?

A)m
B)10m/7
C)10m/7 - 9/7
D)5m/7 + 3/7
E)5m
Here's an algebraic approach:

When we arrange all 7 values in ASCENDING order, with m as the MEDIAN, we get: _ _ _ m _ _ _
All values in set S are equal to or less than 2m
Since we are trying to MAXIMIZE the average, we'll take 2m as a value in set S
So, we get: _ _ _ m _ _ 2m
At this point, we are tying to MAXIMIZE the other values AND make sure all are DISTINCT.
The 2nd biggest value is 2m - 1. So, we get: _ _ _ m _ 2m-1, 2m
The 3rd biggest value is 2m - 2. So, we get: _ _ _ m, 2m-2, 2m-1, 2m
The remaining values must be less than m.
When MAXIMIZING these values, we get: m-3, m-2, m-1, m, 2m-2, 2m-1, 2m

The average = [(m-3)+(m-2)+(m-1)+(m)+(2m-2)+(2m-1)+(2m)]/7 =
= (10m - 9)/7
= [spoiler]10m/7 - 9/7[/spoiler]

Answer: C

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image

User avatar
Legendary Member
Posts: 2663
Joined: Wed Jan 14, 2015 8:25 am
Location: Boston, MA
Thanked: 1153 times
Followed by:128 members
GMAT Score:770

by DavidG@VeritasPrep » Mon Jun 08, 2015 8:17 am
Set S contains seven distinct integers. The median of set S is the integer m, and all values in set S are equal to or less than 2m. What is the highest possible average (arithmetic mean) of all values in set S ?

A)m
B)10m/7
C)10m/7 - 9/7
D)5m/7 + 3/7
E)5m
Our initial set will look like this: ___, ___, ___, m, ___, ___, 2m

We want to maximize the values in order to maximize the average. Well, the greatest possible value for the two slots between 'm' and '2m' would be '2m -1.' and '2m - 2.' (We're told that all the values are distinct. Otherwise, we could have reused 2m.)

And the greatest possible value for the three slots to the left of 'm' would be 'm -1,' 'm -2,' and 'm -3' (Anything greater than 'm' would change the median, which, of course, we can't do.) So now our set looks like this:

m-3, m-2, m-1, m, 2m-2, 2m-1, 2m

Sum = 10m - 9
Number terms = 7
Average = (10m - 9)/7
Veritas Prep | GMAT Instructor

Veritas Prep Reviews
Save $100 off any live Veritas Prep GMAT Course