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A worker is hired for 6 days. He is paid $2 more for each da

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by BTGmoderatorAT » Mon Oct 30, 2017 5:44 pm
A worker is hired for 6 days. He is paid $2 more for each day of work than he was paid for the preceding day of work. How much was he paid for the first day of work?

(1) His total wages for the 6 days were $150.
(2) He was paid 150 percent of his first day's pay for the sixth day

What's the best way to determine whether statement 1 is sufficient?
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Source: — Data Sufficiency |

by Jay@ManhattanReview » Mon Oct 30, 2017 9:31 pm
ardz24 wrote:A worker is hired for 6 days. He is paid $2 more for each day of work than he was paid for the preceding day of work. How much was he paid for the first day of work?

(1) His total wages for the 6 days were $150.
(2) He was paid 150 percent of his first day's pay for the sixth day

What's the best way to determine whether statement 1 is sufficient?
Say the worker is paid $x on the first day, thus for the 6 days, he's paid x, (x+2), (x+4), (x+6), (x+8), and (x+10), respectively.

(1) His total wages for the 6 days were $150.

=> x + (x+2) + (x+4) + (x+6) + (x+8) + (x+10) = 6x + 30

=> 6x+ 30 = 150 => x = $20. Sufficient.

(2) He was paid 150 percent of his first day's pay for the sixth day

=> x+10 = 150% of x = 1.5x

x + 10 = 1.5x => x = $20. Sufficient.

The correct answer: D

Hope this helps!

-Jay

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