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If \(8^c\cdot \sqrt8=\dfrac{8^a}{8^b}\) then \(a = ?\)

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Re: If \(8^c\cdot \sqrt8=\dfrac{8^a}{8^b}\) then \(a = ?\)

by psarma » Thu Oct 01, 2020 3:40 pm
\(8^c\) . \(\sqrt{8}\) = \(8^{\left(c+\frac{1}{\left(2\right)}\right)}\)
Likewise, \(8^a\) / \(8^b\) = \(8^{a-b}\)
Thus, c+1/2=a-b
or a = b+c+1/2

Option E
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