VJesus12 wrote:A certain school principal must choose 5 students to attend a field trip out of a group of 10 students. In addition, out of the 5 chosen students, the principal must select a note-taker and a treasurer. How many different ways are there for the principal to select the 5 students and then select the treasurer and the note-taker?
A. 1,260
B. 2,520
C. 5,040
D. 6,020
E. 10,080
Number of options for treasurer = 10. (Any of the 10 students.)
Number of options for note-taker = 9. (Any of the 9 remaining students.)
From the remaining 8 students, the number of ways to choose 3 to complete the group attending the field trip = 8C3 = (8*7*6)/(3*2*1) = 56.
To combine the options above, we multiply:
10*9*56 = 5040.
The correct answer is
C.
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