M7MBA wrote: ↑Thu Sep 17, 2020 1:03 am
If \(a\) is the units digit of \(7^{47}\) and \(b\) is the rightmost nonzero digit in \(125^{10}\cdot 28^{15}.\) What is the value of \(a+b?\)
A) 1
B) 2
C) 5
D) 6
F) 8
Answer:
D
Solution:
Recall the units digit pattern of powers of 7 is 7-9-3-1. Since the exponent 47 is 3 more than a multiple of 4, 7^47 has a units digit of 3. So a = 3.
Let’s now determine the rightmost nonzero digit of 125^10 x 28^15:
125^10 x 28^15 = (5^3)^10 x (2^2 x 7)^15 = 5^30 x 2^30 x 7^15 = 7^15 x 10^30
We see that the rightmost nonzero digit of 125^10 x 28^15 is the units digit of 7^15 since multiplying by 10^30 means attaching 30 zeros to the end of 7^15.
Since the exponent 15 is also 3 more than a multiple of 4, 7^15 has a units digit of 3. So b = 3. Finally, a + b = 3 + 3 = 6.
Answer: D 
