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A difficult math, pls help to explain

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by Anurag@Gurome » Sat Sep 03, 2011 3:57 am
tracyyahoo wrote:if 2^x+2^x+2^x+2^x=2^n, what is x in terms of n?
--> 2^x+2^x+2^x+2^x = 2^n
--> 4*(2^x) = 2^n
--> (2^2)*(2^x) = 2^n
--> 2^(x+2) = 2^n

Hence, x = n - 2

The correct answer is D.
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by Abhishek009 » Sat Sep 03, 2011 6:33 am
tracyyahoo wrote:if 2^x+2^x+2^x+2^x=2^n, what is x in terms of n?

a)n/4
b)4n
c)2n
d)n-2
e)n+2

pls explain
Plug in some values of x to find the value of n and get the pattern....


Let x be 0

Then ,

2^x+2^x+2^x+2^x = 2^n

2^0+2^0+2^0+2^0 = 2^2

So n = 2 ; when x = 0


Let x be 1

Then ,

2^x+2^x+2^x+2^x = 2^n

2^1+2^1+2^1+2^1 = 2^3

So n = 3 ; when x is 1


Now U can easily derive the pattern ,

n = x + 2

or x = n - 2.
Abhishek
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