Fractions

This topic has expert replies
User avatar
Legendary Member
Posts: 504
Joined: Tue Apr 19, 2011 1:40 pm
Thanked: 114 times
Followed by:11 members

Fractions

by knight247 » Sat Sep 03, 2011 12:16 pm
If X and Y are positive, which of the following must be greater than 1/(x+y)^5?

1. (x+y)^5 / 2x
2. [(x^5) + (y^5)]/(x+y)
3. [(x^5) - (y^5)]/(x+y)

The OA is [spoiler]2 only[/spoiler]. I agree with 2 being greater than 1/(x+y)^5 but I'm getting 1 also as greater than 1/(x+y)^5. I agree with 3 not being greater than 1/(x+y)^5.
Here is how I'm getting 1 greater than 1/(x+y)^5
I have the habit of solving such fraction comparison problems by cross multiplication.
For 1.
(x+y)^5/2x and 1/(x+y)^5
Cross multiplying we get,
(x+y)^10 and 2x
Since x and y are positive left side is going to be greater than right side. Also if x=y then we would have
(2x)^10 and 2x. Left hand side is greater than right. So why is 1 not greater than 1/(x+y)^5?
Source: — Problem Solving |

Junior | Next Rank: 30 Posts
Posts: 12
Joined: Tue Aug 30, 2011 7:55 pm
Thanked: 1 times

by jbivins » Sat Sep 03, 2011 12:23 pm
For me it was easy to see that it wouldn't always be greater by just picking numbers and plugging them into your simplified statement

say x=y=(1/2)

(2x)^10=(2(1/2))^10=1
2x=2(1/2)=1

Therefore in every case it will not be greater than the (X+Y)^-5