Given: a^2 + c^2 = 202
A, B, C - Positive
What is the value of b - a - c?
1. b^2 + c^2 = 225
b^2-a^2 = 23
(b-a)*(b+a) = 23
You have many combinations which give you 23: 23*1, (23)^2*(1/23)
Plus you cant find out a unique value of C as well
Insuff
2. a^2 + b^2 = 265
Same problem as 1.
Combining 1 and 2
Add (b^2 + c^2 = 225) + (a^2 + b^2 = 265)
2b^2+a^2+c^2 = 490
a^2+c^2 = 202 (given)
2b^2 = 288
b^2 = 144
b = +/- 12
Since B is positive, B = 12
b^2 + c^2 = 225
c^2 = 81
c = 9
b^2-a^2 = 23
a^2 = 121
a = 11
Answer: C
GMAT Club
This topic has expert replies
Source: Beat The GMAT — Data Sufficiency |
-
piyush_nitt
- Master | Next Rank: 500 Posts
- Posts: 424
- Joined: Sun Dec 07, 2008 5:15 pm
- Location: Sydney
- Thanked: 12 times
You have 3 variables a,b and c , therefore you need atleast 3 equation for the solution.4meonly wrote:You are correct
GMAT Club's solution was complicated
hence C












