If 3x + 2y > 20, is 4x + y > 20 ?
(1) x > y + 1
(2) y < 5
(1) x > y + 1
(2) y < 5
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If 3x + 2y > 20, is 4x + y > 20 ?srcc25anu wrote:i tried to plot the above inequalities on a graph and feel its E (cannot be solved even by both statements)
any more explanations on this one???
kevincanspain wrote:If 3x + 2y > 20, is 4x + y > 20 ?
(1) x > y + 1
(2) y < 5
HSPA wrote:Let me use Y<5 one more time with Y= 4, Y= -2, (Y= 6 and Y = 20)
at y = 4 ; 3x+2y>20 will give x>4 => 4x+y > 20 satisfies
at y = -2; 3x+2y>20 will give x>8 => 4x+y > 20 satisfies
at y = 6; 3x+2y>20 will give x>3 => 4x+y >20 is not satisfied
at y =20; x is -ve so 4x is more negitive... so not satisfied
So Y< 5 is doing good.. what am I missing Night reader/Anurag
Your calculations show that the further y grow from 5, the more certain you are that 4x+y is indeed greater than 20. At y=-2, 4x alone is already at 32. Do the opposite: try using a 4<y<5 (get y closer to 5)HSPA wrote:Let me use Y<5 one more time with Y= 4, Y= -2, (Y= 6 and Y = 20)
at y = 4 ; 3x+2y>20 will give x>4 => 4x+y > 20 satisfies
at y = -2; 3x+2y>20 will give x>8 => 4x+y > 20 satisfies
at y = 6; 3x+2y>20 will give x>3 => 4x+y >20 is not satisfied
at y =20; x is -ve so 4x is more negitive... so not satisfied
So Y< 5 is doing good.. what am I missing Night reader/Anurag
4x + y > 20 if 4x + y >= 3x + 2y i.e x >= ykevincanspain wrote:If 3x + 2y > 20, is 4x + y > 20 ?
(1) x > y + 1
(2) y < 5
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