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If the area of a circle in square feet equals its radius in feet, then the circle's radius, in feet, is closest to

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If the area of a circle in square feet equals its radius in feet, then the circle's radius, in feet, is closest to

by M7MBA » Fri Dec 11, 2020 2:36 am

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If the area of a circle in square feet equals its radius in feet, then the circle's radius, in feet, is closest to

A) 0.25
B) 0.32
C) 0.45
D) 0.5
E) 0.65

Answer: B

Source: Economist
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Re: If the area of a circle in square feet equals its radius in feet, then the circle's radius, in feet, is closest to

by swerve » Sun Dec 13, 2020 1:10 pm
M7MBA wrote: ↑
Fri Dec 11, 2020 2:36 am
 If the area of a circle in square feet equals its radius in feet, then the circle's radius, in feet, is closest to

A) 0.25
B) 0.32
C) 0.45
D) 0.5
E) 0.65

Answer: B

Source: Economist
We have that,

\(r=\pi r^2\)

and using the approximation

\(\pi \approx 3.14 \approx \dfrac{22}{7}\)

Therefore,

\(1=\dfrac{22}{7}r \Longrightarrow r=\dfrac{7}{22}\approx 0.32\)
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Re: If the area of a circle in square feet equals its radius in feet, then the circle's radius, in feet, is closest to

by Scott@TargetTestPrep » Mon Dec 14, 2020 7:27 am
M7MBA wrote: ↑
Fri Dec 11, 2020 2:36 am
 If the area of a circle in square feet equals its radius in feet, then the circle's radius, in feet, is closest to

A) 0.25
B) 0.32
C) 0.45
D) 0.5
E) 0.65

Answer: B
Solution:

Let’s let r = the radius of the circle, in feet, and we can create the equation:

πr^2 = r

Dividing both sides by r (since r can’t be 0), we have:

πr = 1

r = 1/π ≈ 0.32

Answer: B


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