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In his ranch, Doug Bo can place a loop of rope, called...

Expert replies
by BTGmoderatorLU » Mon Mar 19, 2018 3:07 pm
in his ranch, Doug Bo can place a loop of rope, called a lasso, once in every two throws around a cow's neck. What is the probability that he will be able to place a lasso around a cow's neck at least once in 5 attempts?

(A) 1/5
(B) 15/32
(C) 1/2
(D) 31/32
(E) 1

The OA is D.

I solved this PS question as follow,

P( putting laaso) =1/2

P ( not putting lasso ) =1/2

Let's assume this person cannot put lasso around cows neck in 5 attempts : P = (1/2)^5=1/32

Then P ( putting lasso a least once) = 1 - (1/32)=31/32. Option D.

Experts, any suggestion? Thanks in advance.
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Source: — Problem Solving |

by Jay@ManhattanReview » Mon Mar 19, 2018 10:27 pm
LUANDATO wrote:in his ranch, Doug Bo can place a loop of rope, called a lasso, once in every two throws around a cow's neck. What is the probability that he will be able to place a lasso around a cow's neck at least once in 5 attempts?

(A) 1/5
(B) 15/32
(C) 1/2
(D) 31/32
(E) 1

The OA is D.

I solved this PS question as follow,

P( putting laaso) =1/2

P ( not putting lasso ) =1/2

Let's assume this person cannot put lasso around cows neck in 5 attempts : P = (1/2)^5=1/32

Then P ( putting lasso a least once) = 1 - (1/32)=31/32. Option D.

Experts, any suggestion? Thanks in advance.
All perfect. Nothing to add. :)

-Jay
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by Jeff@TargetTestPrep » Wed Mar 21, 2018 3:22 pm
LUANDATO wrote:in his ranch, Doug Bo can place a loop of rope, called a lasso, once in every two throws around a cow's neck. What is the probability that he will be able to place a lasso around a cow's neck at least once in 5 attempts?

(A) 1/5
(B) 15/32
(C) 1/2
(D) 31/32
(E) 1
We can use the formula:

P(success in at least one of 5 attempts) = 1 - P(no successes in 5 attempts)

Since P(no successes in 5 attempts) = (1/2)^5 = 1/32, then:

P(success in at least one of 5 attempts) = 1 - 1/32 = 31/32

Answer: D

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