BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

landing on blue

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
User avatar
GMAT Instructor
Posts: 3650
Joined: Wed Jan 21, 2009 4:27 am
Location: India
Thanked: 267 times
Followed by:80 members
GMAT Score:760

landing on blue

by sanju09 » Wed Jul 07, 2010 4:01 am
A game has two spinners. For the first spinner, the probability of landing on blue is 4/5. Independently, for the second spinner, the probability of landing on blue is 1/7. What is the probability that the first spinner lands on blue and the second spinner does not land on blue?
(A) 1/35
(B) 4/35
(C) 6/35
(D) 11/35
(E) 24/35
The mind is everything. What you think you become. -Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com
Top
Source: — Problem Solving |

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 1179
Joined: Sun Apr 11, 2010 9:07 pm
Location: Milpitas, CA
Thanked: 447 times
Followed by:88 members

by Rahul@gurome » Wed Jul 07, 2010 4:41 am
Required probability = 4/5 * ( 1- 1/7) = 4/5 * 6/7 = 24/35

The correct answer is (E).
Rahul Lakhani
Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)
Top
User avatar
Legendary Member
Posts: 748
Joined: Sun Jan 31, 2010 7:54 am
Thanked: 46 times
Followed by:3 members

by outreach » Wed Jul 07, 2010 9:21 am
first spinner, the probability of landing on blue is 4/5.
for the second spinner,
the probability of landing on blue is 1/7
the probability of not landing on blue is 1-1/7=6/7


probability that the first spinner lands on blue and the second spinner does not land on blue
4/5*6/7=24/35
E
-------------------------------------
--------------------------------------
General blog
https://amarnaik.wordpress.com
MBA blog
https://amarrnaik.blocked/
Top
Post new topic Post Reply
• Page 1 of 1